India Defeated Ireland by 8 Wickets in T20 World Cup
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India triumphed over Ireland by eight wickets in their second Group A match of the ICC Men’s T20 World Cup 2024, held at Nassau County International Cricket Stadium in New York.
Indian captain Rohit Sharma led the way with a stellar 52-run performance, featuring seven boundaries. Rishabh Pant added an unbeaten 36 off 26 balls, helping India chase the 97-run target in just 12.2 overs.
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In the first innings, Indian bowlers restricted Ireland to a total of 96. The Irish lineup, led by Paul Stirling, struggled against India’s exceptional bowling.
Gareth Delany was Ireland’s top scorer with 26 runs, while Josh Little (14), Lorcan Tucker (10), and Curtis Campher (12) were the only others to reach double figures.
Hardik Pandya shone with bowling figures of 3/27, with Jasprit Bumrah contributing 2/6 and Arshdeep Singh taking 2/35. Axar Patel and Mohammed Siraj each took a wicket.
During India’s run chase, Virat Kohli (1) was dismissed early while opening with Rohit Sharma. Pant then partnered with Sharma for a 54-run stand. Sharma retired hurt at 52, with Suryakumar Yadav coming in. India clinched the victory in 12.2 overs, with Pant sealing the win with a six.
Following this match, India will face Pakistan in a highly anticipated game at the same venue on June 9.
